<?php
//
// Copyright (C) 1999-2000 Top Management Service, inc. All Rights Reserved.
// Copyright (C) 2001-2002 System Consultants Co.,Ltd. All Rights Reserved.
//
// $Id: holiday.func,v 1.5 2002/06/07 10:35:21 hiboki Exp $
//

/**
 * 
 *
 * @author hiroki KAWAMURA <hiroki@syscon.co.jp>
 * @author yuji TAKAHASHI <yu-ji@syscon.co.jp>
 */


/**********************************
その年及び翌年の祝祭日を全て取得し、連想配列にして返す
***********************************/
function getholidays($arg1,$arg2,$dbSqlObj,$dbExecObj) {

	$bday = $arg2."/01/01";
	$eday = (string)($arg2+1)."/12/31";

	$sqlstr = $dbSqlObj->selectHoliday($bday,$eday);

	$result = $dbExecObj->exeSql($arg1,$sqlstr);
	if (!$result) {
		return 0;
	}

	$count = $dbExecObj->getNumRows($result);
	$i = 0;

	while ($i < $count) {
		$ar_holiday[$dbExecObj->getResult($result,$i,"hdate")] = $dbExecObj->getResult($result,$i,"hname");
		$i++;
	}
	return $ar_holiday;
}

/*******************************
日付が祝祭日かどうかチェック
********************************/
function chkholiday($arg1,$arg2) {
	return $arg1[$arg2];
}
?>